49c^2-28c+4=0

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Solution for 49c^2-28c+4=0 equation:


Simplifying
49c2 + -28c + 4 = 0

Reorder the terms:
4 + -28c + 49c2 = 0

Solving
4 + -28c + 49c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(2 + -7c)(2 + -7c) = 0

Subproblem 1

Set the factor '(2 + -7c)' equal to zero and attempt to solve: Simplifying 2 + -7c = 0 Solving 2 + -7c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -7c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -7c = 0 + -2 -7c = 0 + -2 Combine like terms: 0 + -2 = -2 -7c = -2 Divide each side by '-7'. c = 0.2857142857 Simplifying c = 0.2857142857

Subproblem 2

Set the factor '(2 + -7c)' equal to zero and attempt to solve: Simplifying 2 + -7c = 0 Solving 2 + -7c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -7c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -7c = 0 + -2 -7c = 0 + -2 Combine like terms: 0 + -2 = -2 -7c = -2 Divide each side by '-7'. c = 0.2857142857 Simplifying c = 0.2857142857

Solution

c = {0.2857142857, 0.2857142857}

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